Ideas
Claim
Let (fn) be the sequence of Fibonacci numbers, i.e.
f1=1,f2=1,fn=fn−1+fn−2 for n≥3.
Let (sn)=∑n∞fn. Then the following statement is true:
sn=fn+2−1.
Proof
For n=1, s1=f1=1. And we can know it satisfies the claim, since f3−1=2−1=1.
Assume that the claim is true for some n=k,k∈N:
sk=fk+2−1
We need to show that it also holds for n=k+1:
sk+1=fk+3−1
From the claim:
f1+f2+…+fk=fk+2−1
Adding fk+1 to both sides:
f1+f2+…+fk+fk+1=fk+2−1+fk+1
Using the definition of Fibonacci numbers, this can be written as:
sk+1=fk+3−1
This completes the inductive step. By the principle of mathematical induction, the claim is true for all n∈N.